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Question Number 166585 by mkam last updated on 22/Feb/22
if y = (sinx)^e^x   find ((d ( e^(sin^(−1) y) ))/(d (lnx)))
ify=(sinx)exfindd(esin1y)d(lnx)
Answered by Eric002 last updated on 22/Feb/22
ln(y)=e^x  ln(sin(x))  (dy/dx)=e^x (sin(x))^e^x  )(cot(x)+ln(sin(x))  d(e^(sin^(−1) (y)) )/d(ln(x))=((x e^(sin^(−1) (y)) /(√(1−y^2 )))/dx)dy   =e^x (sin(x))^e^x  (cot(x)+ln(sin(x)))(((xe^(sin^1 (y)) )/( (√(1−y^2 )))))
ln(y)=exln(sin(x))dydx=ex(sin(x))ex)(cot(x)+ln(sin(x))d(esin1(y))/d(ln(x))=xesin1(y)/1y2dxdy=ex(sin(x))ex(cot(x)+ln(sin(x)))(xesin1(y)1y2)

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