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Question Number 20872 by j.masanja06@gmail.com last updated on 05/Sep/17
if  y=[xtan^(−1) x]−[(1/2)ln(1+x^2 )]  show that (1+x^2 )y^(′′) =1
ify=[xtan1x][12ln(1+x2)]showthat(1+x2)y=1
Answered by sma3l2996 last updated on 05/Sep/17
y′=tan^(−1) x+(x/(1+x^2 ))−(x/(1+x^2 ))  y′′=(1/(1+x^2 ))⇔(1+x^2 )y′′=1
y=tan1x+x1+x2x1+x2y=11+x2(1+x2)y=1

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