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If-z-3-x-2-y-2-dx-dt-3-dy-dt-2-find-dz-dt-when-x-4-and-y-1-




Question Number 125996 by bramlexs22 last updated on 16/Dec/20
 If z^3 =x^2 −y^2  , → { (((dx/dt)=3)),(((dy/dt)=2)) :}  find (dz/dt) when x=4 and y=1
Ifz3=x2y2,{dxdt=3dydt=2finddzdtwhenx=4andy=1
Answered by Olaf last updated on 16/Dec/20
z^3  = x^2 −y^2   ⇒ 3z^2 (dz/dt) = 2x(dx/dt)−2y(dy/dt) (1)  x = 4, y = 1 ⇒ z^3  = 4^2 −1^2  = 15^� , z = 15^(1/3)   (1) : 3.15^(2/3) (dz/dt) = 2×4×3−2×1×2 = 20  (dz/dt) = ((20)/(3.15^(2/3) ))  = 3^(−(5/3)) .4.5^(1/3)
z3=x2y23z2dzdt=2xdxdt2ydydt(1)x=4,y=1z3=4212=15¯,z=1513(1):3.1523dzdt=2×4×32×1×2=20dzdt=203.1523=353.4.513
Commented by bramlexs22 last updated on 16/Dec/20
thanks
thanks

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