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Question Number 156520 by aliyn last updated on 12/Oct/21
if ∣ z+6i ∣≤5 find the maximum and minimum value of ∣ z+5∣ ?
ifz+6i∣⩽5findthemaximumandminimumvalueofz+5?
Answered by TheSupreme last updated on 12/Oct/21
x^2 +(6+y)^2 ≤5 (circle center −6i radius (√(5)))  (x+5)^2 +y^2 =θ(x,y) (circle of center −5 radius (√θ))  (√θ)+(√5)=(√(5^2 +6^2 ))  (√θ)−(√5)=(√(5^2 +6^2 ))  min=(√(61))−(√5)  max=(√(61))+(√5)
x2+(6+y)25(circlecenter6iradius5)(x+5)2+y2=θ(x,y)(circleofcenter5radiusθ)θ+5=52+62θ5=52+62min=615max=61+5

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