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If-z-x-jy-show-that-the-locus-arg-z-1-z-j-pi-6-is-a-circle-Find-its-centre-and-radius-




Question Number 15172 by tawa tawa last updated on 07/Jun/17
If  z = x + jy, show that the locus arg{((z − 1)/(z − j))} = (π/6) is a circle . Find its centre  and radius.
$$\mathrm{If}\:\:\mathrm{z}\:=\:\mathrm{x}\:+\:\mathrm{jy},\:\mathrm{show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{locus}\:\mathrm{arg}\left\{\frac{\mathrm{z}\:−\:\mathrm{1}}{\mathrm{z}\:−\:\mathrm{j}}\right\}\:=\:\frac{\pi}{\mathrm{6}}\:\mathrm{is}\:\mathrm{a}\:\mathrm{circle}\:.\:\mathrm{Find}\:\mathrm{its}\:\mathrm{centre} \\ $$$$\mathrm{and}\:\mathrm{radius}.\: \\ $$

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