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In-a-ABC-B-pi-6-C-pi-4-and-D-divides-BC-internally-in-the-ratio-1-3-then-sin-BAD-sin-CAD-equal-to-




Question Number 24959 by adityapratap2585@gmail.com last updated on 29/Nov/17
In a △ABC, ∠B=π/6, ∠C=π/4 and  D divides BC internally in the ratio   1 : 3 then ,  ((sin ∠BAD)/(sin ∠CAD))   equal to__
$$\mathrm{In}\:\mathrm{a}\:\bigtriangleup\mathrm{ABC},\:\angle\mathrm{B}=\pi/\mathrm{6},\:\angle\mathrm{C}=\pi/\mathrm{4}\:\mathrm{and} \\ $$$$\mathrm{D}\:\mathrm{divides}\:\mathrm{BC}\:\mathrm{internally}\:\mathrm{in}\:\mathrm{the}\:\mathrm{ratio}\: \\ $$$$\mathrm{1}\::\:\mathrm{3}\:\mathrm{then}\:,\:\:\frac{\mathrm{sin}\:\angle\mathrm{BAD}}{\mathrm{sin}\:\angle\mathrm{CAD}}\:\:\:\mathrm{equal}\:\mathrm{to\_\_} \\ $$
Answered by myintkhaing last updated on 30/Nov/17
((√2)/6)
$$\frac{\sqrt{\mathrm{2}}}{\mathrm{6}} \\ $$
Answered by myintkhaing last updated on 30/Nov/17

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