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Question Number 105812 by Ar Brandon last updated on 31/Jul/20
In a by-election 20% of the electorate voted for Mr X.  If 5 voters are chosen at random from this electorate, what  is the probability that 20% of the sample voted for Mr X ?  (a) 1    (b) (1/5)    (c) (1/(625))    (d) ((256)/(625))
Inabyelection20%oftheelectoratevotedforMrX.If5votersarechosenatrandomfromthiselectorate,whatistheprobabilitythat20%ofthesamplevotedforMrX?(a)1(b)15(c)1625(d)256625
Answered by Don08q last updated on 31/Jul/20
a = P(X) = ((20)/(100))                       = (1/5)  b = P(X^− ) = 1 − ((20)/(100))                       = (4/5)  20% of 5 voters = 1   P(X = 1) =^5 C_1 ((1/5))^1 ((4/5))^4                        = ((256)/(625))   The answer is D
a=P(X)=20100=15b=P(X)=120100=4520%of5voters=1P(X=1)=5C1(15)1(45)4=256625TheanswerisD
Commented by Ar Brandon last updated on 31/Jul/20
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