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In-a-regular-heptagon-ABCDEFG-2-AC-2-AD-2-AD-2-find-BC-




Question Number 184511 by HeferH last updated on 07/Jan/23
In a regular heptagon ABCDEFG :   (√(2(AC)^2 −(AD)^2 )) − AD = 2   find BC.
$${In}\:{a}\:{regular}\:{heptagon}\:{ABCDEFG}\:: \\ $$$$\:\sqrt{\mathrm{2}\left({AC}\right)^{\mathrm{2}} −\left({AD}\right)^{\mathrm{2}} }\:−\:{AD}\:=\:\mathrm{2} \\ $$$$\:{find}\:{BC}.\: \\ $$

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