in-a-triangle-ABC-we-have-3sinA-4cosB-6-4sinB-3cosA-1-find-C-

Question Number 146048 by ArielVyny last updated on 10/Jul/21

i n a t r i a n g l e A B C w e h a v e

{\begin{cases} 3 s i n \hat{A} + 4 c o s \hat{B} = 6 \\ 4 s i n \hat{B} + 3 c o s \hat{A} = 1 \end{cases}

f i n d \hat{C}

Answered by gsk2684 last updated on 10/Jul/21

s q u a r i n g a n d a d d i n g t o g e t

25 + 24 \sin (A + B) = 37

\sin (180^{0} - C) = \frac{12}{24}

\sin C = \frac{1}{2} \Rightarrow C = \frac{Π}{6}

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