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In-ABC-the-following-relationship-holds-cyc-a-2-b-2-c-2-4-cyc-cos-A-2-




Question Number 176365 by Shrinava last updated on 16/Sep/22
In  △ABC  the following relationship holds:  Σ_(cyc)  (a^2 /(b^2  + c^2 )) + 4 Π_(cyc)  cos A ≤ 2
InABCthefollowingrelationshipholds:cyca2b2+c2+4cyccosA2
Answered by behi834171 last updated on 17/Sep/22
(a^2 /(b^2 +c^2 ))=((b^2 +c^2 −2bc.cosA)/(b^2 +c^2 ))=  =1−((2bc)/(b^2 +c^2 )).cosA≤1  ΠcosA≤((1/2))^3 =(1/8)  ⇒lhs=3−Σ((2bc)/(b^2 +c^2 )).cosA+4ΠcosA≤  ≤3−3×1+4×(1/8)=(1/2)<<2
a2b2+c2=b2+c22bc.cosAb2+c2==12bcb2+c2.cosA1ΠcosA(12)3=18lhs=3Σ2bcb2+c2.cosA+4ΠcosA33×1+4×18=12<<2
Commented by Shrinava last updated on 18/Sep/22
cool dera professor thank you
coolderaprofessorthankyou

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