In-an-RLC-series-circuit-R-1kilo-ohms-L-0-2H-C-1-F-If-the-voltage-source-is-given-by-V-150-sin-377t-V-What-is-the-peak-current-delivered-by-the-source-

Question Number 147418 by jlewis last updated on 20/Jul/21

In an R L C series circuit,

R = 1 kilo ohms, L = 0 . 2 H, C = 1 F .

If the voltage source is given by :

(V = 150 \sin 377 t) V . What is the

peak current delivered by the

source ?

Answered by Olaf_Thorendsen last updated on 20/Jul/21

I = \frac{V}{\sqrt{R^{2} + {(ω L - \frac{1}{ω C})}^{2}}}

I = \frac{150}{\sqrt{1000^{2} + {(377 \times 0.2 - \frac{1}{377 \times 10^{- 6}})}^{2}}}

I = 54, 3 m A

Commented by jlewis last updated on 20/Jul/21

thanks Sir

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