In-an-xy-plane-the-graph-of-the-equation-x-6-2-y-5-2-16-is-a-circle-P-10-5-is-on-the-circle-If-PQ-is-a-diameter-of-the-circle-what-is-the-co-ordinate-at-Q-

Question Number 21925 by >>Umar << last updated on 07/Oct/17

In an xy plane the graph of the equation

{(x - 6)}^{2} + {(y + 5)}^{2} = 16 is a circle . P (10, - 5)

is on the circle . If PQ is a diameter of the

circle, what is the co - ordinate at Q ?

Answered by Tinkutara last updated on 07/Oct/17

C e n t e r o f c i r c l e, C = (6, - 5)

L e t Q = (x, y)

T h e n C i s t h e m i d p o i n t o f P Q .

∴ (\frac{10 + x}{2}, \frac{- 5 + y}{2}) = (6, - 5)

10 + x = 12; y - 5 = - 10

x = 2; y = - 5

Commented by >>Umar << last updated on 07/Oct/17

thank you sir .