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In-convex-polygon-ABCD-AB-10-6-CD-18-ABD-60-BDC-45-and-BD-13-6-9-2-find-AC-




Question Number 188126 by Shrinava last updated on 25/Feb/23
In convex polygon  ABCD  AB = 10 (√6)  ,  CD = 18  ∠ ABD = 60°  ,  ∠ BDC = 45°  and  BD = 13 (√6) + 9 (√2)  find  AC = ?
$$\mathrm{In}\:\mathrm{convex}\:\mathrm{polygon}\:\:\mathrm{ABCD} \\ $$$$\mathrm{AB}\:=\:\mathrm{10}\:\sqrt{\mathrm{6}}\:\:,\:\:\mathrm{CD}\:=\:\mathrm{18} \\ $$$$\angle\:\mathrm{ABD}\:=\:\mathrm{60}°\:\:,\:\:\angle\:\mathrm{BDC}\:=\:\mathrm{45}° \\ $$$$\mathrm{and}\:\:\mathrm{BD}\:=\:\mathrm{13}\:\sqrt{\mathrm{6}}\:+\:\mathrm{9}\:\sqrt{\mathrm{2}} \\ $$$$\mathrm{find}\:\:\mathrm{AC}\:=\:? \\ $$

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