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In-moving-a-body-of-mass-m-up-and-down-a-rough-incline-plane-of-inclination-work-done-is-S-is-length-of-the-planck-and-is-coefficient-of-friction-




Question Number 18581 by Tinkutara last updated on 25/Jul/17
In moving a body of mass m up and  down a rough incline plane of inclination  θ, work done is (S is length of the planck,  and μ is coefficient of friction).
Inmovingabodyofmassmupanddownaroughinclineplaneofinclinationθ,workdoneis(Sislengthoftheplanck,andμiscoefficientoffriction).
Answered by ajfour last updated on 25/Jul/17
W=2μmgScos θ
W=2μmgScosθ
Commented by Arnab Maiti last updated on 25/Jul/17
Force of friction =μmgcosθ  Work done to take the body  up against force of friction is  =μmgcosθ×S  Again when it is taken to down  again work done against force  and friction=μmgScosθ  So total work done against  force of friction, w_1 =2μmgScosθ  The work done against gravitational  force =0 , as final height= initial  height  The work done for change of  position is olso 0, as final position  =initial position.  Hence net work done, W=w_1   ∴ W=2μmgScosθ
Forceoffriction=μmgcosθWorkdonetotakethebodyupagainstforceoffrictionis=μmgcosθ×SAgainwhenitistakentodownagainworkdoneagainstforceandfriction=μmgScosθSototalworkdoneagainstforceoffriction,w1=2μmgScosθTheworkdoneagainstgravitationalforce=0,asfinalheight=initialheightTheworkdoneforchangeofpositionisolso0,asfinalposition=initialposition.Hencenetworkdone,W=w1W=2μmgScosθ
Commented by Tinkutara last updated on 25/Jul/17
Thanks Sir!
ThanksSir!

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