Question Number 19358 by Tinkutara last updated on 10/Aug/17
$$\mathrm{In}\:\mathrm{the}\:\mathrm{arrangement}\:\mathrm{shown}\:\mathrm{in}\:\mathrm{figure} \\ $$$$\mathrm{two}\:\mathrm{beads}\:\mathrm{slide}\:\mathrm{along}\:\mathrm{a}\:\mathrm{smooth} \\ $$$$\mathrm{horizontal}\:\mathrm{rod}.\:\mathrm{The}\:\mathrm{relation}\:\mathrm{between} \\ $$$${v}\:\mathrm{and}\:{v}_{\mathrm{0}} \:\mathrm{in}\:\mathrm{given}\:\mathrm{position}\:\mathrm{will}\:\mathrm{be} \\ $$
Commented by Tinkutara last updated on 10/Aug/17
Answered by ajfour last updated on 10/Aug/17
Commented by ajfour last updated on 10/Aug/17
$$\mathrm{As}\:\mathrm{length}\:\mathrm{of}\:\mathrm{string}\:\mathrm{is}\:\mathrm{constant}, \\ $$$$\mathrm{component}\:\mathrm{of}\:\mathrm{velocities}\:\mathrm{of}\:\mathrm{both} \\ $$$$\mathrm{ends}\:\mathrm{along}\:\mathrm{the}\:\mathrm{string}\:\mathrm{length}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{same}. \\ $$$$\Rightarrow\:\:\:\mathrm{vsin}\:\theta=\mathrm{v}_{\mathrm{0}} \mathrm{cos}\:\theta \\ $$$$\:\:\:\:\:\:\:\mathrm{v}=\mathrm{v}_{\mathrm{0}} \mathrm{cot}\:\theta\:. \\ $$
Commented by Tinkutara last updated on 10/Aug/17
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$