In-the-figure-shown-m-slides-on-inclined-surface-of-wedge-M-If-velocity-of-wedge-at-any-instant-be-v-find-velocity-of-m-with-respect-to-ground-

Question Number 20038 by Tinkutara last updated on 20/Aug/17

In the figure shown, m slides on

inclined surface of wedge M . If velocity

of wedge at any instant be v, find

velocity of m with respect to ground .

Commented by Tinkutara last updated on 20/Aug/17

Answered by ajfour last updated on 21/Aug/17

v = - \frac{d y}{d t}, u_{r e l} = \frac{d x}{d t}

x + y = l (i s c o n s t a n t)

s o \frac{d x}{d t} = - \frac{d y}{d t} \Rightarrow u_{r e l} = v

u = \sqrt{u_{x}^{2} + u_{y}^{2}}

u_{x} = v - u_{r e l} \cos 60 ° = v - \frac{v}{2} = \frac{v}{2}

u_{y} = v_{r e l} \sin 60 ° = \frac{v \sqrt{3}}{2}

H e n c e {b l o c k}^{'} s s p e e d w i t h r e s p e c t

t o g r o u n d u = \sqrt{{(\frac{v}{2})}^{2} + {(\frac{v \sqrt{3}}{2})}^{2}} = v .

Commented by Tinkutara last updated on 21/Aug/17

Thank you very much Sir!