In-triangle-ABC-with-angles-correspondently-Euler-s-line-interescts-BC-at-point-P-Ite-s-put-is-angle-between-Euler-s-line-and-BC-BPH-Then-the-following-is-true-tan-2-c

Question Number 180273 by Shrinava last updated on 09/Nov/22

In triangle ABC with angles α, β, γ

correspondently, {Euler}^{'} s line interescts

BC at point P . {Ite}^{'} s put δ is angle

between {Euler}^{'} s line and BC (∠ BPH) .

Then the following is true

\tan δ = \frac{2 \cos β \cos γ - \cos α}{\sin (β - γ)}