Question Number 43156 by MASANJA J last updated on 07/Sep/18
$${integrate}\:{w}.{r}.{t}\:{x} \\ $$$$\int\frac{{xe}^{{x}} }{\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{dx} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 09/Sep/18
$${x}={tan}\alpha\:\:{dx}={sec}^{\mathrm{2}} \alpha{d}\alpha \\ $$$$\int\frac{{tan}\alpha.{e}^{{tan}\alpha} .{sec}^{\mathrm{2}} \alpha}{{sec}\alpha}{d}\alpha \\ $$$$\int{e}^{{tan}\alpha} \left({tan}\alpha{sec}\alpha\right){d}\alpha \\ $$$$\int{e}^{{tan}\alpha} {d}\left({sec}\alpha\right) \\ $$$${contd}… \\ $$$$ \\ $$