is-g-1-1-2-3-3-5-4-7-a-function-justify-if-this-is-described-by-the-relation-g-x-ax-b-then-what-values-should-be-assigned-to-a-and-b-

Question Number 78685 by berket last updated on 19/Jan/20

i s g = {(1 . 1) . (2.3) . (3 . 5) . (4.7)} a f u n c t i o n ? j u s t i f y i f t h i s i s d e s c r i b e d b y t h e r e l a t i o n g (x) = a x + b t h e n w h a t v a l u e s s h o u l d b e a s s i g n e d t o a a n d b ?

Commented by mr W last updated on 19/Jan/20

s i r : p l e a s e {d o n}^{'} t t y p e t h e w h o l e p o s t i n

o n e s i n g l e l i n e! {i t}^{'} s t e r r i b l e t o r e a d!

Answered by behi83417@gmail.com last updated on 19/Jan/20

yes . it is a function .

notice the : x^{'} s in the : (x, y) .

1 . if the x^{'} s are different, then the f, is

function .

2 . if two x^{'} s are equail, notice to : y^{'} s .

if y^{'} s are equail too, then the f, is function .

if y^{'} s not equail, then the f, is not a function .

let : g (x) = ax + b

g (3) = 5 \Rightarrow 5 = a \times 3 + b = 3 a + b

g (2) = 3 \Rightarrow 3 = a \times 2 + b = 2 a + b

\Rightarrow {\begin{cases} 3 a + b = 5 \\ 2 a + b = 3 \end{cases} \Rightarrow a = 2, b = - 1 \Rightarrow g (x) = 2 x - 1

but : (1, 1) not works with this relation .

I think it is : (1, 0) inested of : (1, 1)