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Is-it-possible-to-find-how-many-real-roots-exist-in-the-equation-x-4-x-3-without-find-all-the-value-of-x-




Question Number 23208 by Joel577 last updated on 27/Oct/17
Is it possible to find how many real roots   exist in the equation  x^4  + ∣x∣ = 3  without find all the value of  x?
Isitpossibletofindhowmanyrealrootsexistintheequationx4+x=3withoutfindallthevalueofx?
Answered by mrW1 last updated on 28/Oct/17
x^4 +∣x∣≥0  f(x)=x^4 +∣x∣ is symmetric, i.e.   f(−x)=f(x)  f(x) is strictly increasing for x>0  and strictly decreasing for x<0  therefore  x^4 +∣x∣=a (a<0) has no real root  x^4 +∣x∣=0 has one real root, x=0  x^4 +∣x∣=a (a>0)has two real roots
x4+x∣⩾0f(x)=x4+xissymmetric,i.e.f(x)=f(x)f(x)isstrictlyincreasingforx>0andstrictlydecreasingforx<0thereforex4+x∣=a(a<0)hasnorealrootx4+x∣=0hasonerealroot,x=0x4+x∣=a(a>0)hastworealroots

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