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Question Number 34485 by candre last updated on 07/May/18
is there a function such that:  ∀x≥0;f(x+T_1 )=f(x)  ∀x≤0;f(x−T_2 )=f(x)  f is diferentiabre in x=0
isthereafunctionsuchthat:x0;f(x+T1)=f(x)x0;f(xT2)=f(x)fisdiferentiabreinx=0
Answered by MJS last updated on 07/May/18
f(x): y=c; c∈R
f(x):y=c;cR

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