Is-this-incorrect-S-2-2-S-2-2-2-S-2S-S-0-Please-explain-why-

Question Number 14113 by FilupS last updated on 28/May/17

Is this incorrect :

S = 2 \times 2 \times \dots

S = 2 (2 \times 2 \times \dots)

S = 2 S

S = 0

Please explain why

Commented by FilupS last updated on 28/May/17

the way i see it

S = 2 \times 2 \times 2 \times \dots

S = 2 (1 \times 2 \times 2 \times \dots)

S \neq 1 \times 2 \times 2 \times \dots

Commented by RasheedSindhi last updated on 28/May/17

If S = 2 \times 2 \times 2 \times \dots

then 1 \times S = 1 \times 2 \times 2 \times \dots

S = 1 \times 2 \times 2 \times 2 \times \dots

Commented by RasheedSindhi last updated on 28/May/17

S = 2 S \Rightarrow 2 S - S = \infty - \infty

\infty - \infty is indeterminte .

Hence S = 0 is not necessarily

true .

Commented by prakash jain last updated on 28/May/17

S = f (2)

f (x) be an analytical function

defined for some A \subset R .

S = 0 \Rightarrow f (x) = 0 \forall x \in A

I think f (x) = 0 is not analytic

so S = 0 cannot be derived using

continuation of f (x) = 0 for x = 2