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Question Number 96321 by Mathudent last updated on 31/May/20
It is given that x^2 =2^x . Find x.
Itisgiventhatx2=2x.Findx.
Commented by bemath last updated on 31/May/20
look qn 96241
lookqn96241
Answered by selea last updated on 31/May/20
2^x =x^2   ln(2^x )=ln(x^2 )  xln(2)=2ln∣x∣  ((lnx)/x)=(l/2)ln(2)  ln(x)e^(ln((1/x))) =ln(√2)  ln(x)e^(−lnx) =ln(√2)  −ln(x)e^(−lnx) =−ln(√2)  since  w(xe^x )=x  where w() is lambert function  w(−lnxe^(−lnx) )=w(−ln(√2))  lnx=−w(−ln(√2))  x=e^(−w(−ln(√2)))    for x>0
2x=x2ln(2x)=ln(x2)xln(2)=2lnxlnxx=l2ln(2)ln(x)eln(1x)=ln2ln(x)elnx=ln2ln(x)elnx=ln2sincew(xex)=xwherew()islambertfunctionw(lnxelnx)=w(ln2)lnx=w(ln2)x=ew(ln2)forx>0
Commented by Mathudent last updated on 31/May/20
Can you solve without using De l′Ambert function?
CanyousolvewithoutusingDelAmbertfunction?
Commented by selea last updated on 31/May/20
U can use Newton Raphson Method
UcanuseNewtonRaphsonMethod
Commented by mr W last updated on 31/May/20

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