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JS-lim-x-3-5-2x-x-2-x-4-x-2-




Question Number 109861 by john santu last updated on 26/Aug/20
  ((JS)/(■★★■))  lim_(x→3)  ((5−2x+(√(x−2)))/(x−4+(√(x−2)))) ?
JS◼◼limx352x+x2x4+x2?
Answered by bemath last updated on 26/Aug/20
Commented by john santu last updated on 26/Aug/20
beautifull
beautifull
Answered by Her_Majesty last updated on 26/Aug/20
((5−2x+(√(x−2)))/(x−4+(√(x−2))))=((6−2x+3(√(x−2)))/(x−6)) ⇒ lim=−1
52x+x2x4+x2=62x+3x2x6lim=1
Commented by bemath last updated on 26/Aug/20
what your method miss ?
whatyourmethodmiss?
Commented by Her_Majesty last updated on 26/Aug/20
((5−2x+(√(x−2)))/(x−4+(√(x−2))))×((x−4−(√(x−2)))/(x−4−(√(x−2))))=  =(((x−3)(6−2x+3(√(x−2))))/((x−3)(x−6)))=((6−2x+3(√(x−2)))/(x−6))
52x+x2x4+x2×x4x2x4x2==(x3)(62x+3x2)(x3)(x6)=62x+3x2x6
Commented by bemath last updated on 26/Aug/20
cooll....nice
cooll.nice
Answered by 1549442205PVT last updated on 26/Aug/20
lim _(x→3) ((5−2x+(√(x−2)))/(x−4+(√(x−2)))) =   _(L′Hopital)   lim_(x→3) ((−2+(1/(2(√(x−2)))))/(1+(1/(2(√(x−2))))))  =((−2+(1/2))/(1+(1/2)))=((−3/2)/(3/2))=−1
limx352x+x2x4+x2=LHopitallimx32+12x21+12x2=2+121+12=3/23/2=1

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