k-0-1-k-2k-n-

Question Number 186187 by aba last updated on 02/Feb/23

\underset{k = 0}{\sum^{+ \infty}} {(- 1)}^{k} (_{2 k}^{n}) = ?

Commented by mr W last updated on 02/Feb/23

f o r k = 0 \dots + \infty

(\begin{matrix} n \\ 2 k \end{matrix}) i s n o n - s e n s e, n o m a t t e r w h a t

v a l u e n h a s . s o p l e a s e t e l l w h a t y o u

m e a n w i t h (\begin{matrix} n \\ 2 k \end{matrix}) .

Commented by aba last updated on 02/Feb/23

\underset{k = 0}{\sum^{+ \infty}} {(- 1)}^{k} C_{n}^{2 k} = ?

Commented by mr W last updated on 02/Feb/23

a s i s a i d f o r k = 0 t o + \infty, (_{n}^{2 k}) o r C_{n}^{2 k} i s

n o t d e f i n e d e x c e p t n = 0 . b u t t h e n t h e

q u e s t i o n i s \underset{k = 0}{\sum^{+ \infty}} {(- 1)}^{k} = ?, w h i c h i s a l s o

n o n - s e n s e . t h e r e f o r e t h e q u e s t i o n i s

n o n - s e n s e . i f y o u h a v e c o p i e d t h e

q u e s t i o n f r o m s o m e w h e r e, c h e c k

a g a i n i f y o u h a v e c o p i e d c o r r e c t e l y .

i f y o u h a v e c r e a t e d t h e q u e s t i o n b y

y o u r s e l f, t h e n {i t}^{'} s a b a d a t t e m p t .

Commented by aba last updated on 02/Feb/23

thank you sir

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