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k-0-1-n-2n-1-z-2n-14-




Question Number 106688 by pticantor last updated on 06/Aug/20
Σ_(k=0) ^∞ (((−1)^n )/((2n+1)!))z^(2n−14) =?
$$\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!}{z}^{\mathrm{2}{n}−\mathrm{14}} =? \\ $$

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