k-1-n-i-1-k-i-k-

Question Number 126543 by pticantor last updated on 21/Dec/20

\underset{k = 1}{\sum^{n}} \underset{i = 1}{\prod^{k}} i^{k} = ? ? ?

Answered by MJS_new last updated on 21/Dec/20

= \underset{k = 1}{\sum^{n}} {(k!)}^{k}

I {don}^{'} t think this can be further simplified

you could write it as

1! + {(2!)}^{2} + {(3!)}^{3} + \dots {(n!)}^{n}

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