Question Number 152889 by SANOGO last updated on 02/Sep/21
$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{k}^{\alpha} }{\left({n}+\mathrm{1}\right)^{\alpha} \:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\mathrm{1}+{n}\alpha\right)}=\frac{\mathrm{1}}{\mathrm{6}{o}}\: \\ $$$$\alpha=? \\ $$$$\alpha=?{q} \\ $$
Commented by mr W last updated on 02/Sep/21
$${i}\:{red}\:{flagged}\:{this}\:{and}\:{other}\:{posts}\:{of} \\ $$$${yours}. \\ $$
Commented by SANOGO last updated on 02/Sep/21
$${je}\:{ne}\:{comprend}\:{pas} \\ $$
Commented by puissant last updated on 03/Sep/21