LCM-a-3-5-a-3a-HCF-a-3-5-a-1-5-a-a-

Question Number 94025 by Rasheed.Sindhi last updated on 16/May/20

LCM (a, \frac{3}{5} a) = 3 a \land HCF (a, \frac{3}{5} a) = \frac{1}{5} a

a = ?

Commented by som(math1967) last updated on 16/May/20

sir, if a = 5 then L . C . M = 15

i . e 3 \times 5

HCF = 1 i . e \frac{1}{5} \times 5 = 1

also if a = 1

LCM = 3 i . e 3 \times 1

HCF = \frac{1}{5}

also valid when a \in R

so I think a is any real number

Commented by Rasheed.Sindhi last updated on 16/May/20

T h a n X S i r!

Commented by Rasheed.Sindhi last updated on 16/May/20

I f a \in Z ?

Commented by som(math1967) last updated on 17/May/20

If a = - 3 [- 3 \in Z]

∴ LCM of - 3, \frac{- 9}{5} is - 9

i . e 3 \times - 3 HCF is \frac{- 3}{5} i . e - 3 \times \frac{1}{5}

∴ true if a \in Z

also we know Z \in R

Commented by Rasheed.Sindhi last updated on 17/May/20

T h a n k s a g a i n S i r!

A c t u l l y I m e a n t a, \frac{3}{5} a & \frac{1}{5} a a l l

b e l o n g i n g t o i n t e g e r s!

S o r r y t h a t I {d i d n}^{'} t m a d e i t c l e a r!