Le-spaghetti-de-Cyril-Lignac-Le-chef-Cyril-Lignac-pre-pare-des-spaghettis-Mais-au-moment-de-les-plonger-dans-l-eau-l-un-tombe-par-terre-et-se-casse-en-trois-morceaux-Le-chef-Lignac-se-demande-

Question Number 152394 by Olaf_Thorendsen last updated on 28/Aug/21

$$\mathrm{Le}\:\mathrm{spaghetti}\:\mathrm{de}\:\mathrm{Cyril}\:\mathrm{Lignac}. \\ $$$$ \\ $$$$\mathrm{Le}\:\mathrm{chef}\:\mathrm{Cyril}\:\mathrm{Lignac}\:\mathrm{pr}\acute {\mathrm{e}pare}\:\mathrm{des} \\ $$$$\mathrm{spaghettis}.\:\mathrm{Mais}\:\mathrm{au}\:\mathrm{moment}\:\mathrm{de}\:\mathrm{les} \\ $$$$\mathrm{plonger}\:\mathrm{dans}\:\mathrm{l}'\mathrm{eau},\:\mathrm{l}'\mathrm{un}\:\mathrm{tombe}\:\mathrm{par} \\ $$$$\mathrm{terre}\:\mathrm{et}\:\mathrm{se}\:\mathrm{casse}\:\mathrm{en}\:\mathrm{trois}\:\mathrm{morceaux}. \\ $$$$ \\ $$$$\mathrm{Le}\:\mathrm{chef}\:\mathrm{Lignac}\:\mathrm{se}\:\mathrm{demande}\:\mathrm{alors} \\ $$$$\mathrm{quelle}\:\mathrm{est}\:\mathrm{la}\:\mathrm{probabilit}\acute {\mathrm{e}}\:\mathrm{de}\:\mathrm{pouvoir} \\ $$$$\mathrm{faire}\:\mathrm{un}\:\mathrm{triangle}\:\mathrm{avec}\:\mathrm{les}\:\mathrm{trois} \\ $$$$\mathrm{morceaux}. \\ $$

Commented by mr W last updated on 28/Aug/21

$${i}\:{got}\:{p}=\frac{\mathrm{1}}{\mathrm{4}}. \\ $$

Commented by mr W last updated on 28/Aug/21

Commented by Olaf_Thorendsen last updated on 28/Aug/21

$$\mathrm{Very}\:\mathrm{good}\:\mathrm{mister}\:\mathrm{W}\:! \\ $$$$\mathrm{You}\:\mathrm{are}\:\mathrm{a}\:\mathrm{boss}\:! \\ $$

Commented by puissant last updated on 28/Aug/21

$${Mr}\:{W}\:{you}\:{are}\:{really}\:{strong}.. \\ $$

Commented by mr W last updated on 28/Aug/21

$${my}\:{solution}: \\ $$$${say}\:{length}\:{of}\:{spaghetti}\:{is}\:\mathrm{1}.\:{it}\:{breaks} \\ $$$${into}\:{three}\:{pieces}\:{with}\:{lengthes} \\ $$$${a},{b},\mathrm{1}−{a}−{b}. \\ $$$${a}>\mathrm{0},\:{b}>\mathrm{0},{a}+{b}<\mathrm{1} \\ $$$$\Rightarrow{red}\:{triangle}\:{area} \\ $$$$ \\ $$$${to}\:{form}\:{a}\:{triangle}\:{with}\:{the}\:\mathrm{3}\:{pieces}: \\ $$$${a}+{b}>\mathrm{1}−{a}+{b}\:\Rightarrow\:{a}+{b}>\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${a}+\left(\mathrm{1}−{a}−{b}\right)>{b}\:\Rightarrow\:{b}<\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${b}+\left(\mathrm{1}−{a}−{b}\right)>{a}\:\Rightarrow\:{a}<\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow{green}\:{triangle}\:{area} \\ $$$${p}=\frac{{green}\:{area}}{{red}\:{area}}=\frac{\mathrm{1}}{\mathrm{4}} \\ $$

Commented by puissant last updated on 28/Aug/21

$${own}\:{Mr}\:{W}.. \\ $$

Commented by peter frank last updated on 28/Aug/21

$$\mathrm{what}\:\mathrm{language}\:\mathrm{is}\:\mathrm{this} \\ $$

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