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Let-a-be-a-positive-number-Then-a-a-1-a-i-a-1-i-a-i-2-a-Where-is-the-mistake-

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Question Number 178725 by ComplexPrime last updated on 20/Oct/22
Let a be a positive number. Then (√a)=(√((−a)(−1)))=(√(−a))∙i=(√(a(−1)))∙i=(√a)∙i^2 =−(√a) Where is the mistake?
Letabeapositivenumber.Thena=(−a)(−1)=−a⋅i=a(−1)⋅i=a⋅i2=−aWhereisthemistake?

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