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let-a-gt-0-and-gt-0-fixed-solve-for-0-the-equation-2a-2-cos-x-2-2-x-a-x-a-4-x-




Question Number 163457 by HongKing last updated on 07/Jan/22
let  a>0  and  𝛌>0  fixed  solve for  (0;∞)  the equation:  2a^2 cos((x/(2λ)) - ((2λ)/x)) = a^(x/𝛌)   +  a^((4𝛌)/x)
leta>0andλ>0fixedsolvefor(0;)theequation:2a2cos(x2λ2λx)=axλ+a4λx
Commented by mr W last updated on 07/Jan/22
always x=2λ
alwaysx=2λ

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