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Let-A-x-is-a-cubic-polynomial-and-B-x-x-1-x-2-x-3-Find-how-many-C-x-so-that-B-C-x-B-x-A-x-




Question Number 21656 by Joel577 last updated on 30/Sep/17
Let A(x) is a cubic polynomial and B(x) = (x −1)(x − 2)(x − 3)  Find how many C(x) so that  B(C(x)) = B(x) . A(x)
LetA(x)isacubicpolynomialandB(x)=(x1)(x2)(x3)FindhowmanyC(x)sothatB(C(x))=B(x).A(x)
Commented by Joel577 last updated on 01/Oct/17
The answer isn′t given to me.   Pls explain, Sir
Theanswerisntgiventome.Plsexplain,Sir
Commented by alex041103 last updated on 30/Sep/17
Isn′t it 3?
Isntit3?
Commented by alex041103 last updated on 01/Oct/17
I′m not exactly sure but...here it is.  For short let me put A(x).B(x)=AB  and C(x)=C  ⇒B(C)=AB  (C−1)(C−2)(C−3)=AB  C^3 −6C^2 +11C−6=AB  C^3 −6C^2 +11C−(6+AB)=0=P(C)  And because P(C) is a cubic polinomial  in terms of C, then as stated in the  Fundamental theorem of Algebra,  for C there are three solutions(real  and complex).  The solutions will be in terms of A(x).B(x)  ⇒C will be a function of x  ⇒There are three C(x) that satisfy  B(C(x))=A(x).B(x)
Imnotexactlysurebuthereitis.ForshortletmeputA(x).B(x)=ABandC(x)=CB(C)=AB(C1)(C2)(C3)=ABC36C2+11C6=ABC36C2+11C(6+AB)=0=P(C)AndbecauseP(C)isacubicpolinomialintermsofC,thenasstatedintheFundamentaltheoremofAlgebra,forCtherearethreesolutions(realandcomplex).ThesolutionswillbeintermsofA(x).B(x)CwillbeafunctionofxTherearethreeC(x)thatsatisfyB(C(x))=A(x).B(x)
Commented by Joel577 last updated on 01/Oct/17
but the options are  19  22  24  27  32
buttheoptionsare1922242732

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