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let-ABC-be-a-triangle-AB-c-AC-b-BC-a-Show-that-ABC-is-right-tan-B-2-a-c-b-




Question Number 117818 by snipers237 last updated on 13/Oct/20
 let ABC  be a triangle AB=c  AC=b  BC=a  Show that ABC is right ⇔  tan((B/2))=((a+c)/b)
letABCbeatriangleAB=cAC=bBC=aShowthatABCisrighttan(B2)=a+cb
Commented by 1549442205PVT last updated on 14/Oct/20
Question is′nt exact.Example,ΔABC  A=90°   ,B=60°,a=BC=2⇒AB=c=2.sin30=1  AC=b=2.sin60°=(√3)  tan(B/2)=tan30°=(1/( (√3)))≠((a+c)/b)=((2+1)/( (√3)))=(√3)  You should look at your question
Questionisntexact.Example,ΔABCA=90°,B=60°,a=BC=2AB=c=2.sin30=1AC=b=2.sin60°=3tanB2=tan30°=13a+cb=2+13=3Youshouldlookatyourquestion
Commented by snipers237 last updated on 14/Oct/20
Forgive sir , it was  cotan((B/2))=((a+c)/b)
Forgivesir,itwascotan(B2)=a+cb

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