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Let-ABCD-be-a-convex-quadrilateral-and-M-a-point-in-its-interior-such-that-MAB-MBC-MCD-MDA-Prove-that-one-of-the-diagonals-of-ABCD-passes-through-the-midpoint-of-the-other-diagonal-




Question Number 16064 by Tinkutara last updated on 21/Jun/17
Let ABCD be a convex quadrilateral  and M a point in its interior such that  [MAB] = [MBC] = [MCD] = [MDA].  Prove that one of the diagonals of  ABCD passes through the midpoint of  the other diagonal.
LetABCDbeaconvexquadrilateralandMapointinitsinteriorsuchthat[MAB]=[MBC]=[MCD]=[MDA].ProvethatoneofthediagonalsofABCDpassesthroughthemidpointoftheotherdiagonal.
Commented by Tinkutara last updated on 20/Jun/17
Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 24/Jun/17
Bo×oM.sin(BoM)=Do×oM.sin(180−BoM)⇒  ⇒        Bo=Do⇒ AC  passes from midpoint  of BD.
Bo×oM.sin(BoM)=Do×oM.sin(180BoM)Bo=DoACpassesfrommidpointofBD.
Commented by Tinkutara last updated on 27/Jun/17
This is incorrect solution. Should I  post the correct answer?
Thisisincorrectsolution.ShouldIpostthecorrectanswer?
Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 25/Jun/17
[BCM]=[CMD]⇒BM=MD  [BMA]=[DMA]⇒∠BMA=∠DMA  ⇒ { ((BM=MD)),((∠BMo=∠DMo)) :}⇒^(oM=oM)   ΔBMo=ΔDMo  ⇒Bo=Do⇒AC passes trough midpoint  of BD.
[BCM]=[CMD]BM=MD[BMA]=[DMA]BMA=DMA{BM=MDBMo=DMooM=oMΔBMo=ΔDMoBo=DoACpassestroughmidpointofBD.
Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 27/Jun/17
yes ofcorse.please post it.
yesofcorse.pleasepostit.
Commented by Tinkutara last updated on 27/Jun/17
Commented by Tinkutara last updated on 27/Jun/17
This is my book′s solution. Please  explain the last line.
Thisismybookssolution.Pleaseexplainthelastline.
Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 27/Jun/17
we prove that:Do=Bo ,and it is  proves that AC passes trough midpoint  of BD.
weprovethat:Do=Bo,anditisprovesthatACpassestroughmidpointofBD.

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