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let-and-the-roots-of-x-3-2x-1-0-find-the-value-of-A-2-2-2-and-B-3-3-3-




Question Number 64066 by mathmax by abdo last updated on 12/Jul/19
let α ,β and λ the roots of x^3 +2x−1 =0 find the value of  A =α^2  +β^2  +λ^2  and  B =α^3  +β^3  +λ^3  .
letα,βandλtherootsofx3+2x1=0findthevalueofA=α2+β2+λ2andB=α3+β3+λ3.
Answered by MJS last updated on 12/Jul/19
the solutions are  α=u+v  β=(−(1/2)−((√3)/2)i)u+(−(1/2)+((√3)/2)i)v  λ=(−(1/2)+((√3)/2)i)u+(−(1/2)−((√3)/2)i)v  A=6uv  B=3(u^3 +v^3 )  u=((−(q/2)+((√(3(4p^3 +27q^2 ))/(18))))^(1/3)   v=((−(q/2)−((√(3(4p^3 +27q^2 ))/(18))))^(1/3)   A=−2p  B=−3q  p=2  q=−1  A=−4  B=3
thesolutionsareα=u+vβ=(1232i)u+(12+32i)vλ=(12+32i)u+(1232i)vA=6uvB=3(u3+v3)u=q2+3(4p3+27q2183v=q23(4p3+27q2183A=2pB=3qp=2q=1A=4B=3
Commented by mathmax by abdo last updated on 12/Jul/19
thank you sir mjs
thankyousirmjs

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