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Question Number 131049 by mathmax by abdo last updated on 31/Jan/21
let f(x)=∫_0 ^∞  ((cos(xt))/(x^2  +t^2 ))dt  calculate ∫_0 ^1 f(x)dx
letf(x)=0cos(xt)x2+t2dtcalculate01f(x)dx
Answered by mindispower last updated on 01/Feb/21
f(x)=∫_0 ^∞ ((cos(xt))/(x^2 +t^2 ))dt  t=xr⇒dt=xdr  =(1/x)∫_0 ^∞ ((cos(r))/(1+r^2 ))=(1/x).(1/2)Re∫_(−∞) ^∞ (e^(ir) /(1+r^2 ))dr  =(1/(2x))Res((e^(ir) /(1+r^2 )),r=i)=((iπ)/x),(e^(−1) /(2i))=(π/(xe))  ∫_0 ^1 f(x)dx,not exist
f(x)=0cos(xt)x2+t2dtt=xrdt=xdr=1x0cos(r)1+r2=1x.12Reeir1+r2dr=12xRes(eir1+r2,r=i)=iπx,e12i=πxe01f(x)dx,notexist

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