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let-f-x-0-pi-ln-x-2-2x-cos-1-d-with-x-lt-1-give-a-simple-form-of-f-x-




Question Number 33587 by abdo imad last updated on 19/Apr/18
let f(x)=∫_0 ^π ln (x^2  −2x cosθ +1)dθ  with ∣x∣<1  give a simple form of f(x).
letf(x)=0πln(x22xcosθ+1)dθwithx∣<1giveasimpleformoff(x).

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