Question Number 42482 by maxmathsup by imad last updated on 26/Aug/18
$${let}\:{f}\left({x}\right)={e}^{−\mathrm{2}{x}} \:{arctan}\left({x}\right) \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{3}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie}\:. \\ $$
Commented by maxmathsup by imad last updated on 29/Aug/18
$$\left.\mathrm{1}\right)\:{we}\:{have}\:{by}\:{leibniz}\:{formula}\:{f}^{\left({n}\right)} \left({x}\right)\:=\:\sum_{{k}=\mathrm{0}} ^{{n}} \:{C}_{{n}} ^{{k}} \:\:{arctan}^{\left({k}\right)} {x}\left({x}\right)\left({e}^{−\mathrm{2}{x}} \right)^{\left({n}−{k}\right)} \\ $$$$=\left(−\mathrm{2}\right)^{{n}} \:{e}^{−\mathrm{2}{x}} \:{arctan}\left({x}\right)\:+\sum_{{k}=\mathrm{1}} ^{{n}} \:{C}_{{n}} ^{{k}} \:\:{arctan}^{\left({k}\right)} \left({x}\right)\:\left({e}^{−\mathrm{2}{x}} \right)^{\left({n}−{k}\right)} \:{but} \\ $$$${arctan}^{\left(\mathrm{1}\right)} \left({x}\right)\:=\frac{\mathrm{1}}{\mathrm{1}+{x}^{\mathrm{2}} }\:\Rightarrow{arctan}^{\left({k}\right)} \left({x}\right)=\left(\frac{\mathrm{1}}{\mathrm{1}+{x}^{\mathrm{2}} }\right)^{\left({k}−\mathrm{1}\right)} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}{i}}\left\{\:\frac{\mathrm{1}}{{x}−{i}}\:−\frac{\mathrm{1}}{{x}+{i}}\right\}^{\left({k}−\mathrm{1}\right)} \:=\frac{\mathrm{1}}{\mathrm{2}{i}}\left\{\:\frac{\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} \left({k}−\mathrm{1}\right)!}{\left({x}−{i}\right)^{{k}} }\:−\frac{\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} \left({k}−\mathrm{1}\right)!}{\left({x}+{i}\right)^{{k}} }\right\} \\ $$$$=\frac{\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} \left({k}−\mathrm{1}\right)!}{\mathrm{2}{i}}\left\{\:\frac{\mathrm{1}}{\left({x}−{i}\right)^{{k}} }\:−\frac{\mathrm{1}}{\left({x}+{i}\right)^{{k}} }\right\}\:\:{also}\:{we}\:{have}\:\left({e}^{−\mathrm{2}{x}} \right)^{\left({n}−{k}\right)} =\left(−\mathrm{2}\right)^{{n}−{k}} \:{e}^{−\mathrm{2}{x}} \\ $$$$\Rightarrow \\ $$$${f}^{\left({n}\right)} \left({x}\right)\:=\left(−\mathrm{2}\right)^{{n}} \:{e}^{−\mathrm{2}{x}} {arctanx}\:+\sum_{{k}=\mathrm{1}} ^{{n}} \:{C}_{{n}} ^{{k}} \:\:\frac{\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} \left({k}−\mathrm{1}\right)!}{\mathrm{2}{i}}\left\{\frac{\mathrm{1}}{\left({x}−{i}\right)^{{k}} }\:−\frac{\mathrm{1}}{\left({x}+{i}\right)^{{k}} }\right\}\left(−\mathrm{2}\right)^{{n}−{k}} \:{e}^{−\mathrm{2}{x}} \\ $$$$ \\ $$
Commented by maxmathsup by imad last updated on 29/Aug/18
$$\left.\mathrm{2}\right)\:{x}=\mathrm{0}\:\Rightarrow{f}^{\left({n}\right)} \left(\mathrm{0}\right)\:=\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\:{C}_{{n}} ^{{k}} \:\:\frac{\left(−\mathrm{1}\right)^{\boldsymbol{{k}}−\mathrm{1}} \left(\boldsymbol{{k}}−\mathrm{1}\right)!}{\mathrm{2}{i}}\left\{\:\frac{\mathrm{1}}{\left(−{i}\right)^{{k}} }\:−\frac{\mathrm{1}}{{i}^{{k}} }\right\}\left(−\mathrm{2}\right)^{{n}−{k}} \\ $$$${f}^{\left({n}\right)} \left(\mathrm{0}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}{i}}\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\:\:\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} \left({k}−\mathrm{1}\right)!\:\:\frac{{n}!}{{k}!\left({n}−{k}\right)!}\left\{\:{e}^{\frac{{ik}\pi}{\mathrm{2}}} \:−\:{e}^{−\frac{{ik}\pi}{\mathrm{2}}} \right\} \\ $$$$=\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\frac{\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} {n}!}{{k}\left({n}−{k}\right)!}\:{sin}\left(\frac{{k}\pi}{\mathrm{2}}\right) \\ $$
Commented by maxmathsup by imad last updated on 29/Aug/18
$$\left.\mathrm{3}\right)\:{we}\:{have}\:{f}\left({x}\right)\:=\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\:\frac{{f}^{\left({n}\right)} \left(\mathrm{0}\right)}{{n}!}\:{x}^{{n}} \:\:=\:{f}\left(\mathrm{0}\right)\:+\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\:\frac{{f}^{\left({n}\right)} \left(\mathrm{0}\right)}{{n}!}\:{x}^{{n}} \:\:\:\:\:\:\left({f}\left({o}\right)=\mathrm{0}\right) \\ $$$$\:=\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\left(\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\frac{\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} }{{k}\left({n}−{k}\right)!}\:{sin}\left(\frac{{k}\pi}{\mathrm{2}}\right)\right)\:{x}^{{n}} \:\:. \\ $$