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Let-f-x-sin-3-2x-for-pi-4-x-pi-4-then-Df-1-1-8-a-b-b-so-a-b-




Question Number 161114 by cortano last updated on 12/Dec/21
  Let f(x)= sin^3 (2x) for −(π/4)≤x≤(π/4)   then Df^(−1) ((1/8))=(a/(b(√b))) so  { ((a=?)),((b=?)) :}
$$\:\:{Let}\:{f}\left({x}\right)=\:\mathrm{sin}\:^{\mathrm{3}} \left(\mathrm{2}{x}\right)\:{for}\:−\frac{\pi}{\mathrm{4}}\leqslant{x}\leqslant\frac{\pi}{\mathrm{4}} \\ $$$$\:{then}\:{Df}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{8}}\right)=\frac{{a}}{{b}\sqrt{{b}}}\:{so}\:\begin{cases}{{a}=?}\\{{b}=?}\end{cases} \\ $$

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