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Question Number 38722 by maxmathsup by imad last updated on 28/Jun/18
let f(x)= (x+1)e^(−x)   and  g(x)=ln(2+x^2 )  1) calculate fog(x) and gof(x)  2) calculate  (fog)^′ (x) and (gof)^′ (x).
letf(x)=(x+1)exandg(x)=ln(2+x2)1)calculatefog(x)andgof(x)2)calculate(fog)(x)and(gof)(x).
Commented by math khazana by abdo last updated on 30/Jun/18
1) fog(x)=f(g(x))=(g(x)+1)e^(−g(x))   ={ln(2+x^2 )+1} e^(−ln(2+x^2 )) = ((1+ln(2+x^2 ))/(2+x^2 ))  gof(x)=g(f(x))= ln(2+f^2 (x))  =ln(2+(x+1)^2 e^(−2x) )  2)(fog)^′ (x)=((((2x)/(2+x^2 ))(2+x^2 ) −2xln(2+x^2 ))/((2+x^2 )^2 ))  = ((2x −2xln(2+x^2 ))/((2+x^2 )^2 )) .  (gof)^′ (x) = ((2(x+1)e^(−2x)  −2(x+1)^2 e^(−2x) )/(2+(x+1)^2  e^(−2x) ))  =(({2x+2−2x^2  −4x−2}e^(−2x) )/(2+(x+1)^2 e^(−2x) ))  =(((−2x^2 −2x)e^(−2x) )/(2+(x+1)^2 e^(−2x) ))  = ((−2x^2  −2x)/(2 e^(2x)  +(x+1)^2 )) .
1)fog(x)=f(g(x))=(g(x)+1)eg(x)={ln(2+x2)+1}eln(2+x2)=1+ln(2+x2)2+x2gof(x)=g(f(x))=ln(2+f2(x))=ln(2+(x+1)2e2x)2)(fog)(x)=2x2+x2(2+x2)2xln(2+x2)(2+x2)2=2x2xln(2+x2)(2+x2)2.(gof)(x)=2(x+1)e2x2(x+1)2e2x2+(x+1)2e2x={2x+22x24x2}e2x2+(x+1)2e2x=(2x22x)e2x2+(x+1)2e2x=2x22x2e2x+(x+1)2.

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