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let-f-x-x-1-x-2-cos-pix-1-prove-that-f-x-0-have-a-solurion-inside-0-1-2-use-newton-method-to-find-a-approximate-value-of-




Question Number 57406 by Abdo msup. last updated on 03/Apr/19
let f(x)=(x/( (√(1+x^2 )))) +cos(πx)  1) prove that f(x)=0 have a solurion α inside ]0,1[  2) use newton method to find a approximate   value of α .
$${let}\:{f}\left({x}\right)=\frac{{x}}{\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}\:+{cos}\left(\pi{x}\right) \\ $$$$\left.\mathrm{1}\left.\right)\:{prove}\:{that}\:{f}\left({x}\right)=\mathrm{0}\:{have}\:{a}\:{solurion}\:\alpha\:{inside}\:\right]\mathrm{0},\mathrm{1}\left[\right. \\ $$$$\left.\mathrm{2}\right)\:{use}\:{newton}\:{method}\:{to}\:{find}\:{a}\:{approximate}\: \\ $$$${value}\:{of}\:\alpha\:. \\ $$
Commented by kaivan.ahmadi last updated on 04/Apr/19
f(0)=1>0  ,f(1)=(1/( (√2)))−1<0  ⇒f(0)f(1)<0⇒f has at least one   slution in [0,1]
$${f}\left(\mathrm{0}\right)=\mathrm{1}>\mathrm{0}\:\:,{f}\left(\mathrm{1}\right)=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}−\mathrm{1}<\mathrm{0} \\ $$$$\Rightarrow{f}\left(\mathrm{0}\right){f}\left(\mathrm{1}\right)<\mathrm{0}\Rightarrow{f}\:{has}\:{at}\:{least}\:{one}\: \\ $$$${slution}\:{in}\:\left[\mathrm{0},\mathrm{1}\right] \\ $$

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