Question Number 55270 by maxmathsup by imad last updated on 20/Feb/19
$${let}\:{f}\left({x}\right)={x}^{{n}} {arctan}\left({x}^{\mathrm{2}} \right)\:\:{with}\:{n}\:{integr}\:{natural} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{f}\:{at}\:{integr}\:{serie}\:. \\ $$$$ \\ $$
Commented by maxmathsup by imad last updated on 02/Mar/19
$$\left.\mathrm{1}\right)\:{leibniz}\:{formula}\:{give}\:\:{f}^{\left({n}\right)} \left({x}\right)=\sum_{{k}=\mathrm{0}} ^{{n}} \:{C}_{{n}} ^{{k}} \:\:\left({x}^{{n}} \right)^{\left({k}\right)} \:\:\left({arctan}\left({x}^{\mathrm{2}} \right)\right)^{\left({n}−{k}\right)} \\ $$$${but}\:\left({x}^{{n}} \right)^{\left({k}\right)} ={n}\left({n}−\mathrm{1}\right)…\left({n}−{k}+\mathrm{1}\right){x}^{{n}−{k}} \:=\frac{{n}!}{\left({n}−{k}\right)!}\:{x}^{{n}−{k}} \:\:\:{if}\:{k}\leqslant{n}\:\Rightarrow \\ $$$${f}^{\left({n}\right)} \left({x}\right)\:=\sum_{{k}=\mathrm{0}} ^{{n}} \:\frac{{n}!}{{k}!\left({n}−{k}\right)!}\:\frac{{n}!}{\left({n}−{k}\right)!}\:{x}^{{n}−{k}} \:\left\{{arctan}\left({x}^{\mathrm{2}} \right)\right\}^{\left.\right)\left.{n}−{k}\right)} \\ $$$$=\sum_{{k}=\mathrm{0}} ^{{n}} \:\:\:\frac{\left({n}!\right)^{\mathrm{2}} }{{k}!\left\{\left({n}−{k}\right)!\right\}^{\mathrm{2}} }\:\left\{\:{arctan}\left({x}^{\mathrm{2}} \right)\right\}^{\left({n}−{k}\right)} \:\:\:{let}\:{find}\:\left({arctan}\left({x}^{\mathrm{2}} \right)\right)^{\left({m}\right)} \\ $$$${we}\:{have}\:\:\left\{{arctan}\left({x}^{\mathrm{2}} \right)\right\}^{\left(\mathrm{1}\right)} =\frac{\mathrm{2}{x}}{\mathrm{1}+{x}^{\mathrm{4}} }\:=\frac{\mathrm{2}{x}}{\left({x}^{\mathrm{2}} −{i}\right)\left({x}^{\mathrm{2}} \:+{i}\right)}\:=\frac{\mathrm{2}{x}}{\left({x}−\sqrt{{i}}\right)\left({x}+\sqrt{{i}}\right)\left({x}−\sqrt{−{i}}\right)\left({x}+\sqrt{−{i}}\right)} \\ $$$$=\frac{\mathrm{2}{x}}{\left({x}−{e}^{\frac{{i}\pi}{\mathrm{4}}} \right)\left({x}+{e}^{\frac{{i}\pi}{\mathrm{4}}} \right)\left({x}−{e}^{−\frac{{i}\pi}{\mathrm{4}}} \right)\left({x}+{e}^{−\frac{{i}\pi}{\mathrm{4}}} \right)}\:={F}\left({x}\right)=\frac{{a}}{{x}−{e}^{\frac{{i}\pi}{\mathrm{4}}} }\:+\frac{{b}}{{x}+{e}^{\frac{{i}\pi}{\mathrm{4}}} }\:+\frac{{c}}{{x}−{e}^{−\frac{{i}\pi}{\mathrm{4}}} }\:+\frac{{d}}{{x}+{e}^{−\frac{{i}\pi}{\mathrm{4}}} } \\ $$$${a}\:=\frac{\mathrm{2}\:{e}^{\frac{{i}\pi}{\mathrm{4}}} }{\mathrm{2}{e}^{\frac{{i}\pi}{\mathrm{4}}} \left(\mathrm{2}{i}\:{sin}\left(\frac{\pi}{\mathrm{4}}\right)\right)\left(\mathrm{2}{cos}\left(\frac{\pi}{\mathrm{4}}\right)\right)}\:=\:\frac{\mathrm{1}}{\mathrm{4}{i}\frac{\mathrm{1}}{\mathrm{2}}}\:=\frac{\mathrm{1}}{\mathrm{2}{i}} \\ $$$${b}\:=\frac{−\mathrm{2}\:{e}^{\frac{{i}\pi}{\mathrm{4}}} }{\left(−\mathrm{2}{e}^{\frac{{i}\pi}{\mathrm{4}}} \right)\left(−\mathrm{2}{cos}\left(\frac{\pi}{\mathrm{4}}\right)\right)\left(−\mathrm{2}{i}\:{sin}\left(\frac{\pi}{\mathrm{4}}\right)\right)}\:=\frac{\mathrm{1}}{\mathrm{2}{i}} \\ $$$${c}\:=\frac{\mathrm{2}{e}^{−\frac{{i}\pi}{\mathrm{4}}} }{\left(−\mathrm{2}{isin}\left(\frac{\pi}{\mathrm{4}}\right)\right)\left(\mathrm{2}{cos}\left(\frac{\pi}{\mathrm{4}}\right)\right)\left(\mathrm{2}{e}^{−\frac{{i}\pi}{\mathrm{4}}} \right)}\:=−\frac{\mathrm{1}}{\mathrm{2}{i}} \\ $$$${d}\:=\frac{−\mathrm{2}{e}^{−\frac{{i}\pi}{\mathrm{4}}} }{\left(−\mathrm{2}{cos}\left(\frac{\pi}{\mathrm{4}}\right)\right)\left(\mathrm{2}{i}\:{sin}\left(\frac{\pi}{\mathrm{4}}\right)\right)\left(−\mathrm{2}{e}^{−\frac{{i}\pi}{\mathrm{4}}} \right)}\:=−\frac{\mathrm{1}}{\mathrm{2}{i}}\:\Rightarrow \\ $$$$\left({arctan}\left({x}^{\mathrm{2}} \right)\right)^{\left(\mathrm{1}\right)} \:=\frac{\mathrm{1}}{\mathrm{2}{i}}\left\{\frac{\mathrm{1}}{{x}−{e}^{\frac{{i}\pi}{\mathrm{4}}} }\:+\frac{\mathrm{1}}{{x}+{e}^{\frac{{i}\pi}{\mathrm{4}}} }\:−\frac{\mathrm{1}}{{x}−{e}^{−\frac{{i}\pi}{\mathrm{4}}} }\:−\frac{\mathrm{1}}{{x}+{e}^{−\frac{{i}\pi}{\mathrm{4}}} }\right\}\:\Rightarrow \\ $$$$\left({arctan}\left({x}^{\mathrm{2}} \right)\right)^{\left({m}\right)} =\frac{\mathrm{1}}{\mathrm{2}{i}}\left(−\mathrm{1}\right)^{{m}−\mathrm{1}} \left({m}−\mathrm{1}\right)!\left\{\:\frac{\mathrm{1}}{\left({x}−{e}^{\frac{{i}\pi}{\mathrm{4}}} \right)^{{m}} }\:+\frac{\mathrm{1}}{\left({x}+{e}^{\frac{{i}\pi}{\mathrm{4}}} \right)^{{m}} }\:−\frac{\mathrm{1}}{\left({x}−{e}^{−\frac{{i}\pi}{\mathrm{4}}} \right)^{{m}} }−\frac{\mathrm{1}}{\left({x}+{e}^{−\frac{{i}\pi}{\mathrm{4}}} \right)}\right\}\:\Rightarrow \\ $$$${f}^{\left({n}\right)} \left({x}\right)\:=\frac{\mathrm{1}}{\mathrm{2}{i}}\sum_{{k}=\mathrm{0}} ^{{n}} \:\:\frac{\left({n}!\right)^{\mathrm{2}} }{{k}!\left\{\left({n}−{k}\right)!\right\}^{\mathrm{2}} }\left(−\mathrm{1}\right)^{{n}−{k}−\mathrm{1}} \left({n}−{k}−\mathrm{1}\right)!\left\{\frac{\mathrm{1}}{\left({x}−{e}^{\frac{{i}\pi}{\mathrm{4}}} \right)^{{n}−{k}} }+\frac{\mathrm{1}}{\left({x}+{e}^{\frac{{i}\pi}{\mathrm{4}}} \right)^{{n}−{k}} }−\frac{\mathrm{1}}{\left({x}−{e}^{−\frac{{i}\pi}{\mathrm{4}}} \right)^{{n}−{k}} }\:−\frac{\mathrm{1}}{\left({x}+{e}^{−\frac{{i}\pi}{\mathrm{4}}} \right)^{{n}−{k}} }\right\} \\ $$