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Let-n-be-an-odd-positive-integer-On-some-field-n-gunmen-are-placed-such-that-all-pairwise-distances-between-them-are-different-At-a-signal-every-gunman-takes-out-his-gun-and-shoots-the-closest-gun




Question Number 13893 by Tinkutara last updated on 24/May/17
Let n be an odd positive integer. On  some field, n gunmen are placed such  that all pairwise distances between  them are different. At a signal, every  gunman takes out his gun and shoots  the closest gunman. Prove that:  (a) at least one gunman survives;  (b) no gunman is shot more than 5  times;  (c) the trajectories of the bullets do  not intersect.
Letnbeanoddpositiveinteger.Onsomefield,ngunmenareplacedsuchthatallpairwisedistancesbetweenthemaredifferent.Atasignal,everygunmantakesouthisgunandshootstheclosestgunman.Provethat:(a)atleastonegunmansurvives;(b)nogunmanisshotmorethan5times;(c)thetrajectoriesofthebulletsdonotintersect.
Commented by prakash jain last updated on 25/May/17
Part (a)  Let gunmen be a_1 ,a_2 ,....,a_n   and let us distances are a_(ij) .  Since all distances are different  there exist minimum a_(ij)  for some  value of i and j. Since a_i  will  shoot a_j  and a_j  will shoot a_i .  Case A: a_k (k≠i,k≠j) fires at          a_i  or a_j .  In this case a_i  or a_j  get shot twice.  Since there are only n bullets and  at least person got shot twice then  there will be one person who does  get shot at all. (pigeonhole principle)  Case B: No one else fires at a_i  or a_j   In this case we take a_i  and a_j  out of field  and consider remaining (n−2) gunmen.    Continue this process finally there will  be 3 gunmen left where only case A  is possible.
Part(a)Letgunmenbea1,a2,.,anandletusdistancesareaij.Sincealldistancesaredifferentthereexistminimumaijforsomevalueofiandj.Sinceaiwillshootajandajwillshootai.CaseA:ak(ki,kj)firesataioraj.Inthiscaseaiorajgetshottwice.Sincethereareonlynbulletsandatleastpersongotshottwicethentherewillbeonepersonwhodoesgetshotatall.(pigeonholeprinciple)CaseB:NooneelsefiresataiorajInthiscasewetakeaiandajoutoffieldandconsiderremaining(n2)gunmen.Continuethisprocessfinallytherewillbe3gunmenleftwhereonlycaseAispossible.
Commented by prakash jain last updated on 25/May/17
Part (b) shot<5 times.  Consider a_i  is shot 6 times  by a_j_1  ,...,a_j_6  .  consider hexagon formed by  a_j_1  ...a_j_6  .   A: point a_i  is inside the hexagom  Make a traingle with a_i  and one  side of hexagon say a_j_1  a_(j_2 .)   a_j_1  a_i <a_j_1  a_j_2    a_j_2  a_i <a_j_1  a_j_2    a_j_1  a_j_2   is largest side so ∠a_j_1  aa_j_2  >60°  So six sides of hexagon spawn an  angle >60×6=360° not possible.  case B: a_i  is outside the hexagon.  easy to prove a_i a_j_k  >a_j_k  a_j_l   for  some k,l ∈{1,2,..6} than a_i  is not  shot 6 times.
Part(b)shot<5times.Consideraiisshot6timesbyaj1,,aj6.considerhexagonformedbyaj1aj6.A:pointaiisinsidethehexagomMakeatrainglewithaiandonesideofhexagonsayaj1aj2.aj1ai<aj1aj2aj2ai<aj1aj2aj1aj2islargestsidesoaj1aaj2>60°Sosixsidesofhexagonspawnanangle>60×6=360°notpossible.caseB:aiisoutsidethehexagon.easytoproveaiajk>ajkajlforsomek,l{1,2,..6}thanaiisnotshot6times.
Commented by prakash jain last updated on 25/May/17
Part (c)  Let a_i  shoot a_j  and a_k  shoots a_l .  Let us say a_i a_j  intersects with a_k a_l   Let a_i  shoot a_j  and a_k  shoots a_l .  Consider quadilateral a_i a_k a_j a_l   so a_i a_j  and a_k a_l  are diagonals.  a_i a_k >a_i a_j   a_i a_l >a_i a_j   a_k a_i >a_k a_l   a_k a_j >a_k a_l   Will continue to prove contradiction.
Part(c)Letaishootajandakshootsal.LetussayaiajintersectswithakalLetaishootajandakshootsal.Considerquadilateralaiakajalsoaiajandakalarediagonals.aiak>aiajaial>aiajakai>akalakaj>akalWillcontinuetoprovecontradiction.

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