Question Number 21977 by Tinkutara last updated on 08/Oct/17

Commented by mrW1 last updated on 09/Oct/17
![n=6!×5! (=86400) m=C_1 ^5 ×7!×4!−2×6!×5! (=432000) [or m=C_1 ^5 ×(7!−2!×6!)×4!=432000] ⇒(m/n)=((C_1 ^5 ×7!×4!)/(6!×5!))−2=7−2=5](https://www.tinkutara.com/question/Q21980.png)
Commented by Tinkutara last updated on 09/Oct/17

Commented by mrW1 last updated on 09/Oct/17

Commented by Tinkutara last updated on 09/Oct/17

Commented by Rasheed.Sindhi last updated on 09/Oct/17

Commented by mrW1 last updated on 09/Oct/17
![case 1: BBB[GGGGG]BB since the five girls are together, we treat them as a single object. to arrange this object and the five boys there are 6! ways. to arrange the five girls in the object there are 5! ways. ⇒n=6!5! case 2: BGBB[GGGG]BB we divide the five girls into a single person G and a groupe with 4 persons [GGGG]. there are C_1 ^5 ways to do this. to arrange the four girls in the groupe there are 4! ways. to arrange the five boys and the single girl and the groupe there are 7! ways. ⇒C_1 ^5 ×4!×7! but in these arrangements we have also G[GGGG] and [GGGG]G, both mean that five girls are together. these arrangements must be excluded. ⇒m=C_1 ^5 ×4!×7!−2n ⇒m=C_1 ^5 ×4!×7!−2×6!×5!](https://www.tinkutara.com/question/Q22026.png)
Commented by Rasheed.Sindhi last updated on 09/Oct/17

Commented by mrW1 last updated on 09/Oct/17

Answered by Rasheed.Sindhi last updated on 08/Oct/17

Commented by Rasheed.Sindhi last updated on 08/Oct/17

Commented by Rasheed.Sindhi last updated on 08/Oct/17

Commented by Tinkutara last updated on 09/Oct/17
