Question Number 94657 by msup by abdo last updated on 20/May/20
$${let}\:{u}_{{n}} \:=\sum_{{k}=\mathrm{1}} ^{{n}} \frac{\mathrm{1}}{\left(^{{p}} \sqrt{{k}}\right)} \\ $$$${detetmine}\:{a}\:{equivalent}\:{of}\:{u}_{{n}} \\ $$$$\left({n}\rightarrow+\infty\right) \\ $$$$ \\ $$