Question Number 32296 by abdo imad last updated on 22/Mar/18
$${let}\:\:{u}_{{n}} =\:\frac{\left({n}+\mathrm{1}\right)^{\alpha} \:\:−{n}^{\alpha} }{{n}^{\alpha−\mathrm{1}} }\:\:{with}\:\alpha>\mathrm{1}\:\:{find}\:{lim}_{{n}\rightarrow\infty} {u}_{{n}} \:\:. \\ $$