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let-U-n-pi-4-k-0-n-1-k-2k-1-calcilate-n-0-U-n-




Question Number 34684 by math khazana by abdo last updated on 09/May/18
let U_n = (π/4) −Σ_(k=0) ^n  (((−1)^k )/(2k+1))  calcilate Σ_(n=0) ^∞  U_n
$${let}\:{U}_{{n}} =\:\frac{\pi}{\mathrm{4}}\:−\sum_{{k}=\mathrm{0}} ^{{n}} \:\frac{\left(−\mathrm{1}\right)^{{k}} }{\mathrm{2}{k}+\mathrm{1}} \\ $$$${calcilate}\:\sum_{{n}=\mathrm{0}} ^{\infty} \:{U}_{{n}} \\ $$

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