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Let-x-5pi-12-pi-3-The-maximum-value-of-y-tan-x-2pi-3-tan-x-pi-6-cos-x-pi-6-is-




Question Number 96758 by bobhans last updated on 04/Jun/20
Let x∈ [ −((5π)/(12)) , −(π/3) ] . The maximum   value of y = tan (x+((2π)/3))−tan (x+(π/6)) +cos (x+(π/6))  is ___
Letx[5π12,π3].Themaximumvalueofy=tan(x+2π3)tan(x+π6)+cos(x+π6)is___
Commented by john santu last updated on 04/Jun/20
set m = −x−(π/6), m∈ [ (π/6), (π/4) ]  and 2m ∈ [ (π/3), (π/2) ]. we have   tan (x+((2π)/3)) = −cot (x+(π/6)) = cot m  then y = cot m + tan m + cos m  y = (2/(sin 2m)) + cos m.   since both (2/(sin 2m)) and cos m are  monotonic decreasing in this  case, so y reaches the maksimum  at m = (π/6) , where y_(max)  = (2/(sin (π/3))) + cos (π/6)  = (4/( (√3) )) + ((√3)/2) = ((11(√3))/6) .
setm=xπ6,m[π6,π4]and2m[π3,π2].wehavetan(x+2π3)=cot(x+π6)=cotmtheny=cotm+tanm+cosmy=2sin2m+cosm.sinceboth2sin2mandcosmaremonotonicdecreasinginthiscase,soyreachesthemaksimumatm=π6,whereymax=2sinπ3+cosπ6=43+32=1136.

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