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let-x-and-y-be-positive-reals-such-that-x-3-y-3-x-y-3-30xy-2000-show-that-x-y-10-




Question Number 169445 by infinityaction last updated on 30/Apr/22
     let x and y be positive reals such that      x^3  + y^3  + (x+y)^3  +30xy = 2000      show that x+y = 10
$$ \\ $$$$\:\:\:\mathrm{let}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}\:\mathrm{be}\:\mathrm{positive}\:\mathrm{reals}\:\mathrm{such}\:\mathrm{that} \\ $$$$\:\:\:\:\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{y}^{\mathrm{3}} \:+\:\left(\mathrm{x}+\mathrm{y}\right)^{\mathrm{3}} \:+\mathrm{30xy}\:=\:\mathrm{2000} \\ $$$$\:\:\:\:\mathrm{show}\:\mathrm{that}\:\mathrm{x}+\mathrm{y}\:=\:\mathrm{10} \\ $$
Commented by mr W last updated on 30/Apr/22
i don′t think one can show this,  because it′s not true.
$${i}\:{don}'{t}\:{think}\:{one}\:{can}\:{show}\:{this}, \\ $$$${because}\:{it}'{s}\:{not}\:{true}. \\ $$
Commented by infinityaction last updated on 30/Apr/22
how sir
$${how}\:{sir} \\ $$
Commented by infinityaction last updated on 30/Apr/22
Commented by infinityaction last updated on 30/Apr/22
sorry sir my mistake  not (x+y) replace (x+y)^3
$${sorry}\:{sir}\:{my}\:{mistake} \\ $$$${not}\:\left({x}+{y}\right)\:{replace}\:\left({x}+{y}\right)^{\mathrm{3}} \\ $$
Commented by mr W last updated on 30/Apr/22
it′s still not true!  try with 10(x+y)^2 .
$${it}'{s}\:{still}\:{not}\:{true}! \\ $$$${try}\:{with}\:\mathrm{10}\left({x}+{y}\right)^{\mathrm{2}} . \\ $$
Commented by infinityaction last updated on 30/Apr/22
sir today i am ill due to which these are   mistakes happened i am sorry
$${sir}\:{today}\:{i}\:{am}\:{ill}\:{due}\:{to}\:{which}\:{these}\:{are}\: \\ $$$${mistakes}\:{happened}\:{i}\:{am}\:{sorry} \\ $$
Commented by mr W last updated on 30/Apr/22
get well soon!  i think there are two possibilities:  replace 10(x+y) with 10(x+y)^2  or  replace 10(x+y) with (x+y)^3 .
$${get}\:{well}\:{soon}! \\ $$$${i}\:{think}\:{there}\:{are}\:{two}\:{possibilities}: \\ $$$${replace}\:\mathrm{10}\left({x}+{y}\right)\:{with}\:\mathrm{10}\left({x}+{y}\right)^{\mathrm{2}} \:{or} \\ $$$${replace}\:\mathrm{10}\left({x}+{y}\right)\:{with}\:\left({x}+{y}\right)^{\mathrm{3}} . \\ $$
Commented by infinityaction last updated on 01/May/22
oh yes    thanks you sir
$${oh}\:{yes} \\ $$$$\:\:{thanks}\:{you}\:{sir} \\ $$

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